Find the Discriminant 2x^2+5x+28=0

$2 x^{2} + 5 x + 28 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$5^{2} - 4 (2 \cdot 28)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $5$ to the power of $2$ .

$25 - 4 (2 \cdot 28)$

Multiply $- 4 (2 \cdot 28)$ .

Multiply $2$ by $28$ .

$25 - 4 \cdot 56$

Multiply $- 4$ by $56$ .

$25 - 224$

Subtract $224$ from $25$ .

$- 199$