Find the Discriminant 2x^2+8=-8x

$2 x^{2} + 8 = - 8 x$

Step 1

Add $8 x$ to both sides of the equation.

$2 x^{2} + 8 + 8 x = 0$

Step 2

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 3

Substitute in the values of $a$ , $b$ , and $c$ .

$8^{2} - 4 (2 \cdot 8)$

Step 4

Evaluate the result to find the discriminant.

Simplify each term.

Raise $8$ to the power of $2$ .

$64 - 4 (2 \cdot 8)$

Multiply $- 4 (2 \cdot 8)$ .

Multiply $2$ by $8$ .

$64 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$64 - 64$

Subtract $64$ from $64$ .

$0$