Find the Discriminant 2x^2=8x-8

$2 x^{2} = 8 x - 8$

Step 1

Move all the expressions to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$2 x^{2} - 8 x = - 8$

Add $8$ to both sides of the equation.

$2 x^{2} - 8 x + 8 = 0$

Step 2

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 3

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 8)}^{2} - 4 (2 \cdot 8)$

Step 4

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 8$ to the power of $2$ .

$64 - 4 (2 \cdot 8)$

Multiply $- 4 (2 \cdot 8)$ .

Multiply $2$ by $8$ .

$64 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$64 - 64$

Subtract $64$ from $64$ .

$0$