Find the Discriminant 3u^2-4u+1=0

$3 u^{2} - 4 u + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (3 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (3 \cdot 1)$

Multiply $- 4 (3 \cdot 1)$ .

Multiply $3$ by $1$ .

$16 - 4 \cdot 3$

Multiply $- 4$ by $3$ .

$16 - 12$

Subtract $12$ from $16$ .

$4$