Find the Discriminant 3x^2-24x+48=0

$3 x^{2} - 24 x + 48 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 24)}^{2} - 4 (3 \cdot 48)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 24$ to the power of $2$ .

$576 - 4 (3 \cdot 48)$

Multiply $3$ by $48$ .

$576 - 4 \cdot 144$

Multiply $- 4$ by $144$ .

$576 - 576$

Subtract $576$ from $576$ .

$0$