Find the Discriminant 3x^2-4x=-2

$3 x^{2} - 4 x = - 2$

Add $2$ to both sides of the equation.

$3 x^{2} - 4 x + 2 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (3 \cdot 2)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (3 \cdot 2)$

Multiply $3$ by $2$ .

$16 - 4 \cdot 6$

Multiply $- 4$ by $6$ .

$16 - 24$

Subtract $24$ from $16$ .

$- 8$