Find the Discriminant -3x^2-4x-8=0

$- 3 x^{2} - 4 x - 8 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (- 3 \cdot - 8)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (- 3 \cdot - 8)$

Multiply $- 4 (- 3 \cdot - 8)$ .

Multiply $- 3$ by $- 8$ .

$16 - 4 \cdot 24$

Multiply $- 4$ by $24$ .

$16 - 96$

Subtract $96$ from $16$ .

$- 80$