Find the Discriminant 3x^2+6x=2

$3 x^{2} + 6 x = 2$

Step 1

Subtract $2$ from both sides of the equation.

$3 x^{2} + 6 x - 2 = 0$

Step 2

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 3

Substitute in the values of $a$ , $b$ , and $c$ .

$6^{2} - 4 (3 \cdot - 2)$

Step 4

Evaluate the result to find the discriminant.

Simplify each term.

Raise $6$ to the power of $2$ .

$36 - 4 (3 \cdot - 2)$

Multiply $- 4 (3 \cdot - 2)$ .

Multiply $3$ by $- 2$ .

$36 - 4 \cdot - 6$

Multiply $- 4$ by $- 6$ .

$36 + 24$

Add $36$ and $24$ .

$60$