Find the Discriminant 3x^2-9x+1=0

$3 x^{2} - 9 x + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 9)}^{2} - 4 (3 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 9$ to the power of $2$ .

$81 - 4 (3 \cdot 1)$

Multiply $- 4 (3 \cdot 1)$ .

Multiply $3$ by $1$ .

$81 - 4 \cdot 3$

Multiply $- 4$ by $3$ .

$81 - 12$

Subtract $12$ from $81$ .

$69$