Find the Discriminant 4t^2+8t+4=0

$4 t^{2} + 8 t + 4 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$8^{2} - 4 (4 \cdot 4)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $8$ to the power of $2$ .

$64 - 4 (4 \cdot 4)$

Multiply $- 4 (4 \cdot 4)$ .

Multiply $4$ by $4$ .

$64 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$64 - 64$

Subtract $64$ from $64$ .

$0$