Find the Discriminant 4x^2+9=12x

$4 x^{2} + 9 = 12 x$

Step 1

Subtract $12 x$ from both sides of the equation.

$4 x^{2} + 9 - 12 x = 0$

Step 2

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 3

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 12)}^{2} - 4 (4 \cdot 9)$

Step 4

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 12$ to the power of $2$ .

$144 - 4 (4 \cdot 9)$

Multiply $- 4 (4 \cdot 9)$ .

Multiply $4$ by $9$ .

$144 - 4 \cdot 36$

Multiply $- 4$ by $36$ .

$144 - 144$

Subtract $144$ from $144$ .

$0$