Find the Discriminant 5x^2-6x+1=0

$5 x^{2} - 6 x + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 6)}^{2} - 4 (5 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 6$ to the power of $2$ .

$36 - 4 (5 \cdot 1)$

Multiply $- 4 (5 \cdot 1)$ .

Multiply $5$ by $1$ .

$36 - 4 \cdot 5$

Multiply $- 4$ by $5$ .

$36 - 20$

Subtract $20$ from $36$ .

$16$