Find the Discriminant -6x^2-3x-2=0

$- 6 x^{2} - 3 x - 2 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 3)}^{2} - 4 (- 6 \cdot - 2)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 3$ to the power of $2$ .

$9 - 4 (- 6 \cdot - 2)$

Multiply $- 4 (- 6 \cdot - 2)$ .

Multiply $- 6$ by $- 2$ .

$9 - 4 \cdot 12$

Multiply $- 4$ by $12$ .

$9 - 48$

Subtract $48$ from $9$ .

$- 39$