Find the Discriminant 6x^2-4x+7=0

$6 x^{2} - 4 x + 7 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (6 \cdot 7)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (6 \cdot 7)$

Multiply $- 4 (6 \cdot 7)$ .

Multiply $6$ by $7$ .

$16 - 4 \cdot 42$

Multiply $- 4$ by $42$ .

$16 - 168$

Subtract $168$ from $16$ .

$- 152$