Find the Discriminant 6x^2+9x+3=0

$6 x^{2} + 9 x + 3 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$9^{2} - 4 (6 \cdot 3)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $9$ to the power of $2$ .

$81 - 4 (6 \cdot 3)$

Multiply $- 4 (6 \cdot 3)$ .

Multiply $6$ by $3$ .

$81 - 4 \cdot 18$

Multiply $- 4$ by $18$ .

$81 - 72$

Subtract $72$ from $81$ .

$9$