Find the Discriminant 6x^2-9x+5=0

$6 x^{2} - 9 x + 5 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 9)}^{2} - 4 (6 \cdot 5)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 9$ to the power of $2$ .

$81 - 4 (6 \cdot 5)$

Multiply $- 4 (6 \cdot 5)$ .

Multiply $6$ by $5$ .

$81 - 4 \cdot 30$

Multiply $- 4$ by $30$ .

$81 - 120$

Subtract $120$ from $81$ .

$- 39$