Find the Discriminant 6x^2+x+12=0

$6 x^{2} + x + 12 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$1^{2} - 4 (6 \cdot 12)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

One to any power is one.

$1 - 4 (6 \cdot 12)$

Multiply $- 4 (6 \cdot 12)$ .

Multiply $6$ by $12$ .

$1 - 4 \cdot 72$

Multiply $- 4$ by $72$ .

$1 - 288$

Subtract $288$ from $1$ .

$- 287$