Find the Discriminant -7x^2+16x=8x

$- 7 x^{2} + 16 x = 8 x$

Move all terms to the left side of the equation and simplify.

Subtract $8 x$ from both sides of the equation.

$- 7 x^{2} + 16 x - 8 x = 0$

Subtract $8 x$ from $16 x$ .

$- 7 x^{2} + 8 x = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

$8^{2} - 4 (- 7 \cdot 0)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $8$ to the power of $2$ .

$64 - 4 (- 7 \cdot 0)$

Multiply $- 7$ by $0$ .

$64 - 4 \cdot 0$

Multiply $- 4$ by $0$ .

$64 + 0$

Add $64$ and $0$ .

$64$