Find the Discriminant 8x^2-5x+1=0

$8 x^{2} - 5 x + 1 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 5)}^{2} - 4 (8 \cdot 1)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 5$ to the power of $2$ .

$25 - 4 (8 \cdot 1)$

Multiply $- 4 (8 \cdot 1)$ .

Multiply $8$ by $1$ .

$25 - 4 \cdot 8$

Multiply $- 4$ by $8$ .

$25 - 32$

Subtract $32$ from $25$ .

$- 7$