Find the Discriminant -8x^2+7x-3=0

$- 8 x^{2} + 7 x - 3 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$7^{2} - 4 (- 8 \cdot - 3)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $7$ to the power of $2$ .

$49 - 4 (- 8 \cdot - 3)$

Multiply $- 4 (- 8 \cdot - 3)$ .

Multiply $- 8$ by $- 3$ .

$49 - 4 \cdot 24$

Multiply $- 4$ by $24$ .

$49 - 96$

Subtract $96$ from $49$ .

$- 47$