Find the Discriminant 8x^2+9x+8=0

$8 x^{2} + 9 x + 8 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$9^{2} - 4 (8 \cdot 8)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $9$ to the power of $2$ .

$81 - 4 (8 \cdot 8)$

Multiply $- 4 (8 \cdot 8)$ .

Multiply $8$ by $8$ .

$81 - 4 \cdot 64$

Multiply $- 4$ by $64$ .

$81 - 256$

Subtract $256$ from $81$ .

$- 175$