Find the Discriminant 9x^2-18x+9=0

$9 x^{2} - 18 x + 9 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 18)}^{2} - 4 (9 \cdot 9)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 18$ to the power of $2$ .

$324 - 4 (9 \cdot 9)$

Multiply $- 4 (9 \cdot 9)$ .

Multiply $9$ by $9$ .

$324 - 4 \cdot 81$

Multiply $- 4$ by $81$ .

$324 - 324$

Subtract $324$ from $324$ .

$0$