Find the Discriminant 9x^2-48x+64=0

$9 x^{2} - 48 x + 64 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 48)}^{2} - 4 (9 \cdot 64)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 48$ to the power of $2$ .

$2304 - 4 (9 \cdot 64)$

Multiply $- 4 (9 \cdot 64)$ .

Multiply $9$ by $64$ .

$2304 - 4 \cdot 576$

Multiply $- 4$ by $576$ .

$2304 - 2304$

Subtract $2304$ from $2304$ .

$0$