Find the Discriminant x^2-16x+64=0

$x^{2} - 16 x + 64 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 16)}^{2} - 4 (1 \cdot 64)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 16$ to the power of $2$ .

$256 - 4 (1 \cdot 64)$

Multiply $- 4 (1 \cdot 64)$ .

Multiply $64$ by $1$ .

$256 - 4 \cdot 64$

Multiply $- 4$ by $64$ .

$256 - 256$

Subtract $256$ from $256$ .

$0$