Find the Discriminant -x^2+2x+12=0

$- x^{2} + 2 x + 12 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$2^{2} - 4 (- 1 \cdot 12)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $2$ to the power of $2$ .

$4 - 4 (- 1 \cdot 12)$

Multiply $- 4 (- 1 \cdot 12)$ .

Multiply $- 1$ by $12$ .

$4 - 4 \cdot - 12$

Multiply $- 4$ by $- 12$ .

$4 + 48$

Add $4$ and $48$ .

$52$