Find the Discriminant x^2-40x+400=0

$x^{2} - 40 x + 400 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 40)}^{2} - 4 (1 \cdot 400)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 40$ to the power of $2$ .

$1600 - 4 (1 \cdot 400)$

Multiply $- 4 (1 \cdot 400)$ .

Multiply $400$ by $1$ .

$1600 - 4 \cdot 400$

Multiply $- 4$ by $400$ .

$1600 - 1600$

Subtract $1600$ from $1600$ .

$0$