Find the Discriminant x^2+4x-32=0

$x^{2} + 4 x - 32 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$4^{2} - 4 (1 \cdot - 32)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $4$ to the power of $2$ .

$16 - 4 (1 \cdot - 32)$

Multiply $- 4 (1 \cdot - 32)$ .

Multiply $- 32$ by $1$ .

$16 - 4 \cdot - 32$

Multiply $- 4$ by $- 32$ .

$16 + 128$

Add $16$ and $128$ .

$144$