Find the Discriminant x^2-6x-5=0

$x^{2} - 6 x - 5 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 6)}^{2} - 4 (1 \cdot - 5)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 6$ to the power of $2$ .

$36 - 4 (1 \cdot - 5)$

Multiply $- 4 (1 \cdot - 5)$ .

Multiply $- 5$ by $1$ .

$36 - 4 \cdot - 5$

Multiply $- 4$ by $- 5$ .

$36 + 20$

Add $36$ and $20$ .

$56$