Find the Discriminant y=x^2+3x+9

$y = x^{2} + 3 x + 9$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

$3^{2} - 4 (1 \cdot 9)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $3$ to the power of $2$ .

$9 - 4 (1 \cdot 9)$

Multiply $- 4 (1 \cdot 9)$ .

Multiply $9$ by $1$ .

$9 - 4 \cdot 9$

Multiply $- 4$ by $9$ .

$9 - 36$

Subtract $36$ from $9$ .

$- 27$