Find the Domain and Range log base 3 of x+2

$\log_{3} (x + 2)$

Set the argument in $\log_{3} (x + 2)$ greater than $0$ to find where the expression is defined.

$x + 2 > 0$

Subtract $2$ from both sides of the inequality.

$x > - 2$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- 2, \infty)$

Set-Builder Notation:

${x | x > - 2}$

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${y | y \in ℝ}$

Determine the domain and range.

Domain: $(- 2, \infty), {x | x > - 2}$

Range: $(- \infty, \infty), {y | y \in ℝ}$