Find the Domain and Range y = natural log of x-3+1

$y = \ln (x - 3) + 1$

Set the argument in $\ln (x - 3)$ greater than $0$ to find where the expression is defined.

$x - 3 > 0$

Add $3$ to both sides of the inequality.

$x > 3$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(3, \infty)$

Set-Builder Notation:

${x | x > 3}$

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${y | y \in ℝ}$

Determine the domain and range.

Domain: $(3, \infty), {x | x > 3}$

Range: $(- \infty, \infty), {y | y \in ℝ}$