Find the Domain f^-1(x) = cube root of x+1

$f^{- 1} (x) = \sqrt[3]{x + 1}$

Step 1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 2

Find the Domain f^-1(x) = cube root of x+1

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