Find the Domain log base 4 of x+3

$\log_{4} (x + 3)$

Step 1

Set the argument in $\log_{4} (x + 3)$ greater than $0$ to find where the expression is defined.

$x + 3 > 0$

Step 2

Subtract $3$ from both sides of the inequality.

$x > - 3$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- 3, \infty)$

Set-Builder Notation:

${x | x > - 3}$

Step 4