Find the Domain square root of 3x+4

$\sqrt{3 x + 4}$

Step 1

Set the radicand in $\sqrt{3 x + 4}$ greater than or equal to $0$ to find where the expression is defined.

$3 x + 4 \geq 0$

Step 2

Solve for $x$ .

Subtract $4$ from both sides of the inequality.

$3 x \geq - 4$

Divide each term in $3 x \geq - 4$ by $3$ and simplify.

Divide each term in $3 x \geq - 4$ by $3$ .

$\frac{3 x}{3} \geq \frac{- 4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} \geq \frac{- 4}{3}$

Divide $x$ by $1$ .

$x \geq \frac{- 4}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$x \geq - \frac{4}{3}$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- \frac{4}{3}, \infty)$

Set-Builder Notation:

${x | x \geq - \frac{4}{3}}$

Step 4