Find the Domain square root of 3x-5

$\sqrt{3 x - 5}$

Step 1

Set the radicand in $\sqrt{3 x - 5}$ greater than or equal to $0$ to find where the expression is defined.

$3 x - 5 \geq 0$

Step 2

Solve for $x$ .

Add $5$ to both sides of the inequality.

$3 x \geq 5$

Divide each term in $3 x \geq 5$ by $3$ and simplify.

Divide each term in $3 x \geq 5$ by $3$ .

$\frac{3 x}{3} \geq \frac{5}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} \geq \frac{5}{3}$

Divide $x$ by $1$ .

$x \geq \frac{5}{3}$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[\frac{5}{3}, \infty)$

Set-Builder Notation:

${x | x \geq \frac{5}{3}}$

Step 4