Find the Domain square root of 48/x

$\sqrt{\frac{48}{x}}$

Set the radicand in $\sqrt{\frac{48}{x}}$ greater than or equal to $0$ to find where the expression is defined.

$\frac{48}{x} \geq 0$

Solve for $x$ .

Find all the values where the expression switches from negative to positive by setting each factor equal to $0$ and solving.

$x = 0$

Find the domain of $\frac{48}{x}$ .

Set the denominator in $\frac{48}{x}$ equal to $0$ to find where the expression is undefined.

$x = 0$

The domain is all values of $x$ that make the expression defined.

$(- \infty, 0) \cup (0, \infty)$

The solution consists of all of the true intervals.

$x > 0$

Set the denominator in $\frac{48}{x}$ equal to $0$ to find where the expression is undefined.

$x = 0$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(0, \infty)$

Set-Builder Notation:

${x | x > 0}$