Find the Domain square root of 5x-15

$\sqrt{5 x - 15}$

Step 1

Set the radicand in $\sqrt{5 x - 15}$ greater than or equal to $0$ to find where the expression is defined.

$5 x - 15 \geq 0$

Step 2

Solve for $x$ .

Add $15$ to both sides of the inequality.

$5 x \geq 15$

Divide each term in $5 x \geq 15$ by $5$ and simplify.

Divide each term in $5 x \geq 15$ by $5$ .

$\frac{5 x}{5} \geq \frac{15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} \geq \frac{15}{5}$

Divide $x$ by $1$ .

$x \geq \frac{15}{5}$

Simplify the right side.

Divide $15$ by $5$ .

$x \geq 3$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[3, \infty)$

Set-Builder Notation:

${x | x \geq 3}$

Step 4