Find the Domain square root of x+13

$\sqrt{x + 13}$

Step 1

Set the radicand in $\sqrt{x + 13}$ greater than or equal to $0$ to find where the expression is defined.

$x + 13 \geq 0$

Step 2

Subtract $13$ from both sides of the inequality.

$x \geq - 13$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 13, \infty)$

Set-Builder Notation:

${x | x \geq - 13}$

Step 4