Find the Domain y=(10-2x)/(x^2-7x+10)

$y = \frac{10 - 2 x}{x^{2} - 7 x + 10}$

Set the denominator in $\frac{10 - 2 x}{x^{2} - 7 x + 10}$ equal to $0$ to find where the expression is undefined.

$x^{2} - 7 x + 10 = 0$

Solve for $x$ .

Factor $x^{2} - 7 x + 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $10$ and whose sum is $- 7$ .

$- 5, - 2$

Write the factored form using these integers.

$(x - 5) (x - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$x - 2 = 0$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

The final solution is all the values that make $(x - 5) (x - 2) = 0$ true.

$x = 5, 2$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 2) \cup (2, 5) \cup (5, \infty)$

Set-Builder Notation:

${x | x \neq 2, 5}$

Find the Domain y=(10-2x)/(x^2-7x+10)

Related Questions

Support LCMGCF.com by disabling your adblocker.