Find the Domain y=10/(x^2-36)

$y = \frac{10}{x^{2} - 36}$

Step 1

Set the denominator in $\frac{10}{x^{2} - 36}$ equal to $0$ to find where the expression is undefined.

$x^{2} - 36 = 0$

Step 2

Solve for $x$ .

Add $36$ to both sides of the equation.

$x^{2} = 36$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{36}$

Simplify $\pm \sqrt{36}$ .

Rewrite $36$ as $6^{2}$ .

$x = \pm \sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 6$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, - 6$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, - 6) \cup (- 6, 6) \cup (6, \infty)$

Set-Builder Notation:

${x | x \neq 6, - 6}$

Step 4