Find the Domain y = square root of 8+x

$y = \sqrt{8 + x}$

Step 1

Set the radicand in $\sqrt{8 + x}$ greater than or equal to $0$ to find where the expression is defined.

$8 + x \geq 0$

Step 2

Subtract $8$ from both sides of the inequality.

$x \geq - 8$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 8, \infty)$

Set-Builder Notation:

${x | x \geq - 8}$

Step 4