Find the Domain y=( square root of x+3)/((x+8)(x-2))

$y = \frac{\sqrt{x + 3}}{(x + 8) (x - 2)}$

Step 1

Set the radicand in $\sqrt{x + 3}$ greater than or equal to $0$ to find where the expression is defined.

$x + 3 \geq 0$

Step 2

Subtract $3$ from both sides of the inequality.

$x \geq - 3$

Step 3

Set the denominator in $\frac{\sqrt{x + 3}}{(x + 8) (x - 2)}$ equal to $0$ to find where the expression is undefined.

$(x + 8) (x - 2) = 0$

Step 4

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 8 = 0$

$x - 2 = 0$

Set $x + 8$ equal to $0$ and solve for $x$ .

Set $x + 8$ equal to $0$ .

$x + 8 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

The final solution is all the values that make $(x + 8) (x - 2) = 0$ true.

$x = - 8, 2$

Step 5

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 3, 2) \cup (2, \infty)$

Set-Builder Notation:

${x | x \geq - 3, x \neq 2}$

Step 6