Find the Domain y = square root of x+9

$y = \sqrt{x + 9}$

Step 1

Set the radicand in $\sqrt{x + 9}$ greater than or equal to $0$ to find where the expression is defined.

$x + 9 \geq 0$

Step 2

Subtract $9$ from both sides of the inequality.

$x \geq - 9$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 9, \infty)$

Set-Builder Notation:

${x | x \geq - 9}$

Step 4