Find the Equation Using Slope-Intercept Form m=-1/10 , (-8,0)

$m = - \frac{1}{10}$ , $(- 8, 0)$

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (- \frac{1}{10}) \cdot x + b$

Substitute the value of $x$ into the equation.

$y = (- \frac{1}{10}) \cdot (- 8) + b$

Substitute the value of $y$ into the equation.

$0 = (- \frac{1}{10}) \cdot (- 8) + b$

Find the value of $b$ .

Rewrite the equation as $- \frac{1}{10} \cdot - 8 + b = 0$ .

$- \frac{1}{10} \cdot - 8 + b = 0$

Simplify each term.

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{1}{10}$ into the numerator.

$\frac{- 1}{10} \cdot - 8 + b = 0$

Factor $2$ out of $10$ .

$\frac{- 1}{2 (5)} \cdot - 8 + b = 0$

Factor $2$ out of $- 8$ .

$\frac{- 1}{2 \cdot 5} \cdot (2 \cdot - 4) + b = 0$

Cancel the common factor.

$\frac{- 1}{2 \cdot 5} \cdot (2 \cdot - 4) + b = 0$

Rewrite the expression.

$\frac{- 1}{5} \cdot - 4 + b = 0$

Combine $\frac{- 1}{5}$ and $- 4$ .

$\frac{- - 4}{5} + b = 0$

Multiply $- 1$ by $- 4$ .

$\frac{4}{5} + b = 0$

Subtract $\frac{4}{5}$ from both sides of the equation.

$b = - \frac{4}{5}$

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = - \frac{1}{10} x - \frac{4}{5}$