Find the Equation Using Two Points (0,1) and (5,3)

$(0, 1)$ and $(5, 3)$

Use $y = m x + b$ to calculate the equation of the line, where $m$ represents the slope and $b$ represents the y-intercept.

To calculate the equation of the line, use the $y = m x + b$ format.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{(change in y)}{(change in x)}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{3 - (1)}{5 - (0)}$

Finding the slope $m$ .

Simplify the numerator.

Multiply $- 1$ by $1$ .

$m = \frac{3 - 1}{5 - (0)}$

Subtract $1$ from $3$ .

$m = \frac{2}{5 - (0)}$

Simplify the denominator.

Multiply $- 1$ by $0$ .

$m = \frac{2}{5 + 0}$

Add $5$ and $0$ .

$m = \frac{2}{5}$

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (\frac{2}{5}) x + b$

Substitute the value of $x$ into the equation.

$y = (\frac{2}{5}) \cdot (0) + b$

Substitute the value of $y$ into the equation.

$1 = (\frac{2}{5}) \cdot (0) + b$

Find the value of $b$ .

Rewrite the equation as $\frac{2}{5} \cdot 0 + b = 1$ .

$\frac{2}{5} \cdot 0 + b = 1$

Simplify $\frac{2}{5} \cdot 0 + b$ .

Multiply $\frac{2}{5}$ by $0$ .

$0 + b = 1$

Add $0$ and $b$ .

$b = 1$

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = \frac{2}{5} x + 1$

Find the Equation Using Two Points (0,1) and (5,3)

Related Questions

Support LCMGCF.com by disabling your adblocker.