Find the Equation Using Two Points (1,3) and (-3,-5)

$(1, 3)$ and $(- 3, - 5)$

Use $y = m x + b$ to calculate the equation of the line, where $m$ represents the slope and $b$ represents the y-intercept.

To calculate the equation of the line, use the $y = m x + b$ format.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{(change in y)}{(change in x)}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 5 - (3)}{- 3 - (1)}$

Finding the slope $m$ .

Simplify the numerator.

Multiply $- 1$ by $3$ .

$m = \frac{- 5 - 3}{- 3 - (1)}$

Subtract $3$ from $- 5$ .

$m = \frac{- 8}{- 3 - (1)}$

Simplify the denominator.

Multiply $- 1$ by $1$ .

$m = \frac{- 8}{- 3 - 1}$

Subtract $1$ from $- 3$ .

$m = \frac{- 8}{- 4}$

Divide $- 8$ by $- 4$ .

$m = 2$

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (2) \cdot x + b$

Substitute the value of $x$ into the equation.

$y = (2) \cdot (1) + b$

Substitute the value of $y$ into the equation.

$3 = (2) \cdot (1) + b$

Find the value of $b$ .

Rewrite the equation as $(2) \cdot (1) + b = 3$ .

$(2) \cdot (1) + b = 3$

Multiply $2$ by $1$ .

$2 + b = 3$

Move all terms not containing $b$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$b = 3 - 2$

Subtract $2$ from $3$ .

$b = 1$

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = 2 x + 1$

Find the Equation Using Two Points (1,3) and (-3,-5)

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