Find the Equation Using Two Points (-6,5) , (-3,-3)

$(- 6, 5)$ , $(- 3, - 3)$

Step 1

Use $y = m x + b$ to calculate the equation of the line, where $m$ represents the slope and $b$ represents the y-intercept.

To calculate the equation of the line, use the $y = m x + b$ format.

Step 2

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{(change in y)}{(change in x)}$

Step 3

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Step 4

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 3 - (5)}{- 3 - (- 6)}$

Step 5

Finding the slope $m$ .

Simplify the numerator.

Multiply $- 1$ by $5$ .

$m = \frac{- 3 - 5}{- 3 - (- 6)}$

Subtract $5$ from $- 3$ .

$m = \frac{- 8}{- 3 - (- 6)}$

Simplify the denominator.

Multiply $- 1$ by $- 6$ .

$m = \frac{- 8}{- 3 + 6}$

Add $- 3$ and $6$ .

$m = \frac{- 8}{3}$

Move the negative in front of the fraction.

$m = - \frac{8}{3}$

Step 6

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (- \frac{8}{3}) \cdot x + b$

Substitute the value of $x$ into the equation.

$y = (- \frac{8}{3}) \cdot (- 6) + b$

Substitute the value of $y$ into the equation.

$5 = (- \frac{8}{3}) \cdot (- 6) + b$

Find the value of $b$ .

Rewrite the equation as $- \frac{8}{3} \cdot - 6 + b = 5$ .

$- \frac{8}{3} \cdot - 6 + b = 5$

Simplify each term.

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{8}{3}$ into the numerator.

$\frac{- 8}{3} \cdot - 6 + b = 5$

Factor $3$ out of $- 6$ .

$\frac{- 8}{3} \cdot (3 (- 2)) + b = 5$

Cancel the common factor.

$\frac{- 8}{3} \cdot (3 \cdot - 2) + b = 5$

Rewrite the expression.

$- 8 \cdot - 2 + b = 5$

Multiply $- 8$ by $- 2$ .

$16 + b = 5$

Move all terms not containing $b$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$b = 5 - 16$

Subtract $16$ from $5$ .

$b = - 11$

Step 7

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = - \frac{8}{3} x - 11$

Step 8

Find the Equation Using Two Points (-6,5) , (-3,-3)

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