Find the Equation Using Two Points (-8,-3) , (-12,-2)

$(- 8, - 3)$ , $(- 12, - 2)$

Use $y = m x + b$ to calculate the equation of the line, where $m$ represents the slope and $b$ represents the y-intercept.

To calculate the equation of the line, use the $y = m x + b$ format.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{(change in y)}{(change in x)}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 2 - (- 3)}{- 12 - (- 8)}$

Finding the slope $m$ .

Simplify the numerator.

Multiply $- 1$ by $- 3$ .

$m = \frac{- 2 + 3}{- 12 - (- 8)}$

Add $- 2$ and $3$ .

$m = \frac{1}{- 12 - (- 8)}$

Simplify the denominator.

Multiply $- 1$ by $- 8$ .

$m = \frac{1}{- 12 + 8}$

Add $- 12$ and $8$ .

$m = \frac{1}{- 4}$

Move the negative in front of the fraction.

$m = - \frac{1}{4}$

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (- \frac{1}{4}) \cdot x + b$

Substitute the value of $x$ into the equation.

$y = (- \frac{1}{4}) \cdot (- 8) + b$

Substitute the value of $y$ into the equation.

$- 3 = (- \frac{1}{4}) \cdot (- 8) + b$

Find the value of $b$ .

Rewrite the equation as $- \frac{1}{4} \cdot - 8 + b = - 3$ .

$- \frac{1}{4} \cdot - 8 + b = - 3$

Simplify each term.

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{1}{4}$ into the numerator.

$\frac{- 1}{4} \cdot - 8 + b = - 3$

Factor $4$ out of $- 8$ .

$\frac{- 1}{4} \cdot (4 (- 2)) + b = - 3$

Cancel the common factor.

$\frac{- 1}{4} \cdot (4 \cdot - 2) + b = - 3$

Rewrite the expression.

$- 1 \cdot - 2 + b = - 3$

Multiply $- 1$ by $- 2$ .

$2 + b = - 3$

Move all terms not containing $b$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$b = - 3 - 2$

Subtract $2$ from $- 3$ .

$b = - 5$

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = - \frac{1}{4} x - 5$

Find the Equation Using Two Points (-8,-3) , (-12,-2)

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