Find the Equation with a Point and Slope What is the equation of the line that passes through the point (6,6) and has a slope of 5/3 ?

What is the equation of the line that passes through the point $(6, 6)$ and has a slope of $\frac{5}{3}$ ?

Find the value of $b$ using the formula for the equation of a line.

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (\frac{5}{3}) x + b$

Substitute the value of $x$ into the equation.

$y = (\frac{5}{3}) \cdot (6) + b$

Substitute the value of $y$ into the equation.

$6 = (\frac{5}{3}) \cdot (6) + b$

Find the value of $b$ .

Rewrite the equation as $\frac{5}{3} \cdot 6 + b = 6$ .

$\frac{5}{3} \cdot 6 + b = 6$

Simplify each term.

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$\frac{5}{3} \cdot (3 (2)) + b = 6$

Cancel the common factor.

$\frac{5}{3} \cdot (3 \cdot 2) + b = 6$

Rewrite the expression.

$5 \cdot 2 + b = 6$

Multiply $5$ by $2$ .

$10 + b = 6$

Move all terms not containing $b$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$b = 6 - 10$

Subtract $10$ from $6$ .

$b = - 4$

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = \frac{5}{3} x - 4$