Find the Exact Value (1+0.06/4)^(4/12)-1

${(1 + \frac{0.06}{4})}^{\frac{4}{12}} - 1$

Step 1

Simplify each term.

Divide $0.06$ by $4$ .

${(1 + 0.015)}^{\frac{4}{12}} - 1$

Add $1$ and $0.015$ .

${1.015}^{\frac{4}{12}} - 1$

Cancel the common factor of $4$ and $12$ .

Factor $4$ out of $4$ .

${1.015}^{\frac{4 (1)}{12}} - 1$

Cancel the common factors.

Factor $4$ out of $12$ .

${1.015}^{\frac{4 \cdot 1}{4 \cdot 3}} - 1$

Cancel the common factor.

${1.015}^{\frac{4 \cdot 1}{4 \cdot 3}} - 1$

Rewrite the expression.

${1.015}^{\frac{1}{3}} - 1$

${1.015}^{\frac{1}{3}} - 1$

${1.015}^{\frac{1}{3}} - 1$

Raise $1.015$ to the power of $\frac{1}{3}$ .

$1.0049752 - 1$

$1.0049752 - 1$

Step 2

Subtract $1$ from $1.0049752$ .

$0.0049752$

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